# Chapter 29: Volumes, Arc Lengths, and Surface Areas

> Discs, washers, shells and cross-sections for volumes of revolution, plus arc length and surface area — the full toolkit for turning flat regions into exact 3D measurements.

**Canonical:** https://calculus.kitzo.work/chapter/applications-integrals  
**Level:** Advanced  
**Estimated time:** 55 minutes  
**Exercises:** 8 (auto-marked; answers stay server-side)

## Topics
- Disc method
- Shell method
- Cross-sections
- Arc length
- Parametric arc length
- Surface area of revolution

**Why this matters**

Integrals do more than measure area — they accumulate anything that adds up uniformly: volume, arc length, surface area, mass, work. The disc, washer and shell methods are how you turn a flat 2D region into exact measurements of a 3D solid.

## 1 · The disc method — spinning a region about the x-axis

Rotate the region under y = f(x), a ≤ x ≤ b, about the x-axis. Every vertical slice sweeps a thin disc of radius f(x) and thickness dx, with volume πf(x)² dx. Total: **V = π ∫ₐᵇ f(x)² dx**. For rotation about the y-axis of a region given as x = g(y), do the same with y: V = π ∫ g(y)² dy.

**Worked example**

**Example 1 — Region under y = √x, 0 ≤ x ≤ 4, rotated about the x-axis.**

Step 1: disc radius = √x ⇒ disc area = π(√x)² = πx.

Step 2: V = π ∫₀⁴ x dx = π · [x²/2]₀⁴ = 8π.

Step 3: sanity check — paraboloid-like solid, volume slightly less than π·4²·4/2 = 32π. ✓

## 2 · Washers — rotation with a hole

When the region sits between an outer curve R(x) and an inner curve r(x) (both above the axis), slices sweep out *washers*: annulus area π(R(x)² − r(x)²). Volume: **V = π ∫ₐᵇ (R(x)² − r(x)²) dx**. Rotating about a horizontal line y = k ≠ 0? Shift the radii: use R − k and r − k in place of R and r.

## 3 · The shell method — cylindrical shells

Rotate vertical strips around the **y-axis** (or any y-axis-parallel line). A strip at x with height f(x) and thickness dx sweeps a shell of radius x, height f(x): volume 2π·x·f(x)·dx. Total: **V = 2π ∫ₐᵇ x f(x) dx**. Shells shine when the disc setup forces you to invert y = f(x) — rotating a region described by y = f(x) around the y-axis is the signature shells problem.

**Example 2 — Region bounded by y = x(2 − x) and y = 0, rotated about the y-axis.**

Step 1: shell radius x, shell height 2x − x², thickness dx.

Step 2: V = 2π ∫₀² x(2x − x²) dx = 2π ∫₀² (2x² − x³) dx = 2π [2x³/3 − x⁴/4]₀² = 2π(16/3 − 4) = 8π/3.

Step 3: the disc method would need x = 1 ± √(1 − y), messy square roots — shells win cleanly.

## 4 · Which method when — the summary

  - About the x-axis, region y = f(x): discs/washers, integrate in x.

  - About the y-axis, region y = f(x): shells, integrate in x (usually easiest).

  - About the y-axis, region x = g(y): discs/washers, integrate in y.

  - About the x-axis, region x = g(y): shells, integrate in y.

  - Whole region down to the axis → disc. Region with a hole/between two curves → washer.

## 5 · Volumes of general solids via cross-sections

Slice ANY solid perpendicular to an axis with known cross-sectional area A(x): **V = ∫ₐᵇ A(x) dx**. Squares of side s(x): A = s². Equilateral triangles: A = (√3/4)s². Semicircles of diameter s: A = (π/8)s². E.g. the base region between y = x² and y = 1, with square cross-sections perpendicular to the y-axis: at height y the slice runs from x = −√y to x = +√y, so the square has side 2√y and area A(y) = 4y, giving V = ∫₀¹ 4y dy = 2.

## 6 · Arc length and surface area

Arc length: a small step dx corresponds to ds = √(1 + y′²) dx, so **L = ∫ₐᵇ √(1 + (dy/dx)²) dx**. For parametric curves, use speed: L = ∫ √((dx/dt)² + (dy/dt)²) dt. Surface area of a solid of revolution: **S = 2π ∫ (radius) · ds** = 2π ∫ₐᵇ f(x)√(1 + y′²) dx for rotation about the x-axis.

**Watch out**

The √(1 + y′²) radical usually only cooperates when 1 + y′² is a perfect square — textbook curves are designed that way (y = (2/3)x^(3/2), since y′ = √x). And in surface area the radius is the distance to the axis — not the disc radius squared — missing the ds factor is the classic disaster.

## 7 · Axis-parallel variations

Rotation about y = k (a line parallel to the x-axis): radius becomes |f(x) − k|. About x = h: shell radius becomes |x − h|, and washer setups need g(y) − h. The rule of thumb: always measure the radius from the axis of rotation, never blindly from the coordinate axes — draw the strip, label its radius, then integrate.

**Chapter formula sheet**

Discs: V = π ∫ f(x)² dx · Washers: V = π ∫ (R² − r²) dx

Shells: V = 2π ∫ (radius)(height) dx · Cross-sections: V = ∫ A(x) dx

Arc length: L = ∫ √(1 + y′²) dx = ∫ √((x′)² + (y′)²) dt

Surface: S = 2π ∫ f(x)√(1 + y′²) dx (about x-axis)

Parallel axis y = k: radius = |f(x) − k|

## Common mistakes

  - Writing π(R − r)² instead of π(R² − r²) for washers.

  - Dropping the 2π in the shell formula — that gives πx·f(x), not a shell.

  - Using vertical strips for shells about the x-axis — shells need strips parallel to the axis.

  - Reading 1 + y instead of 1 + y′² under the arc-length radical.

  - In surface area, integrating f(x) instead of f(x)·ds.

## Practice exercises

1. The region under y = √x on [0, 4] is rotated about the x-axis. The volume is:

- A. 8π
- B. 4π
- C. 16π
- D. 2π

2. The region under y = x on [0, 2] rotates about the x-axis. Find the volume (decimal).

3. Find the arc length of y = (2/3)x^(3/2) from x = 0 to x = 3.

4. Rotating a region given as y = f(x) about the y-axis is usually easiest with the:

- A. disc method
- B. shell method
- C. washer method
- D. cross-section method

5. A solid is built on a region in the xy-plane with cross-sections perpendicular to the x-axis that are squares of side f(x) . Its cross-sectional area A(x) is (write like f(x)^2 ):

6. Find the surface area generated by rotating y = x on [0, 1] about the x-axis.

7. For a washer with outer radius R and inner radius r, the cross-sectional area is:

- A. π(R + r)
- B. π(R² − r²)
- C. πR² − r
- D. 2πRr

8. When using the shell method with vertical strips to rotate about the y-axis, the radius of the shell at position x is … (one letter).

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